Đề 34-48
Cau 3: Can bao nhieu voi song co do hoat tinh 92% (8% la hat non lua) de san xuat 1,5m3 voi nhuyen tinh khiet co khoi luong the tich la 1350kg/m3. Biet khoi luong rieng cua hydroxyt Canxi la 2,1g/cm3 va cua nuoc la 1,05 g/cm3. Gia thiet trong voi nhuyen ko co bot khi.
Bai giai:
1,5 m3 voi nhuyen co khoi luong la
1,5x 1350= 2025(kg)
va the tich dac la: Va=1,5 (m3)
Do do co he phuong trinh
VaH2O(m3) + VaCa(OH)2(m3)= 1,5 (m3)
mCa(OH)2 (kg) + mH2O (kg)= 2025 (kg)
↔ mCa(OH)2(kg) + mH2O (kg)= 2025 (kg)
mCa(OH)2/ ρCa(OH)2+ mH2O/ρH2O =1,5 (m3)
↔ mCa(OH)2(kg) + mH2O (kg)= 2025 (kg);
mCa(OH)2/ 2100 + mH2O/ 1050 =1,5 (m3)
↔ mCa(OH)2= 900(kg);
mH2O= 1125(kg)
Luong CaO (voi co hoat tinh 100%) de san xuat 1,5m3 voi nhuyen la
mvoi= 92%. 900. 56/74= 627 (kg)
Cau 1: Phan tich anh huong cua do am den cuong do, khoi luong the tich, do co no the tich cua go?
-Anh huong toi ρwv (hinh ve)
ρwv= Gw/Vw0
Khi vuot qua do am bht thi ρv tang nhanh, Vw0 no? cham.
Khi do am o trong nuoc hap thu thi ρv tang cham, Vw0 no? nhanh
De tien so sanh toan the gioi quy dinh lay do am o 18% cua go la do am tieu chuan. Cac thong so phai qui ve o do am 18%.
ρ18w= ρwv.[1+0,01.(1-K0).(18-w)]
ρwv: khoi luong the tich cua go o W bat ky
k0: he so co
K0= Y0/W
Y0=(V1-V2)/V2. 100%
V1,V2: the tich cua mau truoc va sau khi say.(hinh ve)
Khi thay doi W duoi Wbht thi W go cung thay doi
Khi W↑ thi R↓ nhung khi vuot qua diem bht thi Rgo hau nhu ko thay doi
- Cuong do cua go
Go thuong lam viec trong cac trang thai uon, nen, cat keo
Nen: nen doc tho, nen ngang tho, nen xien tho (hinh ve~)
Rnen= P/F
P: luc tac dung
F: dien tich be mat tac dung
Ruon= M/W
M: momen uong
W: momen chuong uon
Khi tinh toan phai dua ve
R18nd= Rw.[1+α.(W-18)]
α: he so phu thuoc vao chat luong go
Rw= R18nd/ [1+α(W-18)]
Kpc= R18/R18V [(kg/cm2)/(kg/m3)]
Cau 2: The nao la tinh deo hop ly cua hon hop be tong? Phan tich cac yeu to anh huong den tinh deo cua hon hop be tong?
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